-16t^2+12.7t+4=0

Solution for -16t^2+12.7t+4=0 equation:

-16t^2+12.7t+4=0

a = -16; b = 12.7; c = +4;
Δ = b2-4ac
Δ = 12.72-4·(-16)·4
Δ = 417.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.7)-\sqrt{417.29}}{2*-16}=\frac{-12.7-\sqrt{417.29}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.7)+\sqrt{417.29}}{2*-16}=\frac{-12.7+\sqrt{417.29}}{-32}
$